ALGORITHM:
1. Mark each process that has a row in the Allocation matrix of all zeros.
2. Initialize a temporary vectorW to equal the Available vector.
3. Find an indexi such that processi is currently unmarked and thei th row ofQ
is less than or equal to W . That is,Q ik … Wk, for 1 … k … m . If no such row is
found, terminate the algorithm.
4. If such a row is found, mark processi and add the corresponding row of the
allocation matrix to W . That is, setWk = Wk + Aik, for 1 … k … m . Return
to step 3.
SOURCE CODE:
#include<stdio.h>
static int mark[20];
int i,j,np,nr;
int main()
{
int alloc[10][10],request[10][10],avail[10],r[10],w[10];
printf("\nEnter the no of process: ");
scanf("%d",&np);
printf("\nEnter the no of resources: ");
scanf("%d",&nr);
for(i=0;i<nr;i++)
{
printf("\nTotal Amount of the Resource R%d: ",i+1);
scanf("%d",&r[i]);
}
printf("\nEnter the request matrix:");
for(i=0;i<np;i++)
for(j=0;j<nr;j++)
scanf("%d",&request[i][j]);
printf("\nEnter the allocation matrix:");
for(i=0;i<np;i++)
for(j=0;j<nr;j++)
scanf("%d",&alloc[i][j]);
/*Available Resource calculation*/
for(j=0;j<nr;j++)
{
avail[j]=r[j];
for(i=0;i<np;i++)
{
avail[j]-=alloc[i][j];
}
}
//marking processes with zero allocation
for(i=0;i<np;i++)
{
int count=0;
for(j=0;j<nr;j++)
{
if(alloc[i][j]==0)
count++;
else
break;
}
if(count==nr)
mark[i]=1;
}
// initialize W with avail
for(j=0;j<nr;j++)
w[j]=avail[j];
//mark processes with request less than or equal to W
for(i=0;i<np;i++)
{
int canbeprocessed=0;
if(mark[i]!=1)
{
for(j=0;j<nr;j++)
{
if(request[i][j]<=w[j])
canbeprocessed=1;
else
{
canbeprocessed=0;
break;
}
}
if(canbeprocessed)
{
mark[i]=1;
for(j=0;j<nr;j++)
w[j]+=alloc[i][j];
}
}
}
//checking for unmarked processes
int deadlock=0;
for(i=0;i<np;i++)
if(mark[i]!=1)
deadlock=1;
if(deadlock)
printf("\n Deadlock detected");
else
printf("\n No Deadlock possible");
}
OUTPUT:
Enter the no of process: 4
Enter the no of resources: 5
Total Amount of the Resource R1: 2
Total Amount of the Resource R2: 1
Total Amount of the Resource R3: 1
Total Amount of the Resource R4: 2
Total Amount of the Resource R5: 1
Enter the request matrix:0 1 0 0 1
0 0 1 0 1
0 0 0 0 1
1 0 1 0 1
Enter the allocation matrix:1 0 1 1 0
1 1 0 0 0
0 0 0 1 0
0 0 0 0 0
Deadlock detected
--------------------------------
1. Mark each process that has a row in the Allocation matrix of all zeros.
2. Initialize a temporary vectorW to equal the Available vector.
3. Find an indexi such that processi is currently unmarked and thei th row ofQ
is less than or equal to W . That is,Q ik … Wk, for 1 … k … m . If no such row is
found, terminate the algorithm.
4. If such a row is found, mark processi and add the corresponding row of the
allocation matrix to W . That is, setWk = Wk + Aik, for 1 … k … m . Return
to step 3.
SOURCE CODE:
#include<stdio.h>
static int mark[20];
int i,j,np,nr;
int main()
{
int alloc[10][10],request[10][10],avail[10],r[10],w[10];
printf("\nEnter the no of process: ");
scanf("%d",&np);
printf("\nEnter the no of resources: ");
scanf("%d",&nr);
for(i=0;i<nr;i++)
{
printf("\nTotal Amount of the Resource R%d: ",i+1);
scanf("%d",&r[i]);
}
printf("\nEnter the request matrix:");
for(i=0;i<np;i++)
for(j=0;j<nr;j++)
scanf("%d",&request[i][j]);
printf("\nEnter the allocation matrix:");
for(i=0;i<np;i++)
for(j=0;j<nr;j++)
scanf("%d",&alloc[i][j]);
/*Available Resource calculation*/
for(j=0;j<nr;j++)
{
avail[j]=r[j];
for(i=0;i<np;i++)
{
avail[j]-=alloc[i][j];
}
}
//marking processes with zero allocation
for(i=0;i<np;i++)
{
int count=0;
for(j=0;j<nr;j++)
{
if(alloc[i][j]==0)
count++;
else
break;
}
if(count==nr)
mark[i]=1;
}
// initialize W with avail
for(j=0;j<nr;j++)
w[j]=avail[j];
//mark processes with request less than or equal to W
for(i=0;i<np;i++)
{
int canbeprocessed=0;
if(mark[i]!=1)
{
for(j=0;j<nr;j++)
{
if(request[i][j]<=w[j])
canbeprocessed=1;
else
{
canbeprocessed=0;
break;
}
}
if(canbeprocessed)
{
mark[i]=1;
for(j=0;j<nr;j++)
w[j]+=alloc[i][j];
}
}
}
//checking for unmarked processes
int deadlock=0;
for(i=0;i<np;i++)
if(mark[i]!=1)
deadlock=1;
if(deadlock)
printf("\n Deadlock detected");
else
printf("\n No Deadlock possible");
}
OUTPUT:
Enter the no of process: 4
Enter the no of resources: 5
Total Amount of the Resource R1: 2
Total Amount of the Resource R2: 1
Total Amount of the Resource R3: 1
Total Amount of the Resource R4: 2
Total Amount of the Resource R5: 1
Enter the request matrix:0 1 0 0 1
0 0 1 0 1
0 0 0 0 1
1 0 1 0 1
Enter the allocation matrix:1 0 1 1 0
1 1 0 0 0
0 0 0 1 0
0 0 0 0 0
Deadlock detected
--------------------------------
its not working
ReplyDeleteIts working...just Do some correction...I have done It..
ReplyDeletehello there, can i know where is the correction
DeleteWrite this statment "Static int mark[20]" after int main()...and in last write return 0;
ReplyDeleteShowing segmentation fault (core dumped)
ReplyDelete