FCFS CPU Scheduling - C Program - Operating Systems

#include<stdio.h>
struct process
{
char name;
int at,bt,ct,tt;
float ntt;
}p[10];
int n;
void sortByArrival()
{
struct process temp;
int i,j;
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
{
if(p[i].at>p[j].at)
{
temp=p[i];
p[i]=p[j];
p[j]=temp;
}
}
}

void main()
{
int i,j,time=0;
char c;
 printf("Enter no of processes:");
 scanf("%d",&n);
 for(i=0,c='A';i<n;i++,c++)
 {
 p[i].name=c;
 printf("\nEnter the arrival time of process%d: ",i+1);
 scanf("%d",&p[i].at);
 printf("\nEnter the burst time of process%d: ",i+1);
 scanf("%d",&p[i].bt);
}

sortByArrival();

printf("\nName\tArrival Time\tBurst Time\tTurnAround Time\t  Normalized TT");

for(i=0;i<n;i++)
{
time+=p[i].bt;
p[i].ct=time;
p[i].tt=p[i].ct-p[i].at;
p[i].ntt=((float)p[i].tt/p[i].bt);
printf("\n%c\t\t%d\t\t%d\t\t%d\t\t%f",p[i].name,p[i].at,p[i].bt,p[i].tt,p[i].ntt);
}
}

OUTPUT:

Enter no of processes:5

Enter the arrival time of process1: 0

Enter the burst time of process1: 3

Enter the arrival time of process2: 2

Enter the burst time of process2: 6

Enter the arrival time of process3: 4

Enter the burst time of process3: 4

Enter the arrival time of process4: 6

Enter the burst time of process4: 5

Enter the arrival time of process5: 8

Enter the burst time of process5: 2

Name    Arrival Time    Burst Time      TurnAround Time   Normalized TT

A               0                                3               3               1.000000

B               2                                6               7               1.166667

C               4                                4               9               2.250000

D               6                               5               12              2.400000

E               8                                2               12              6.000000